Tom O'Connell
- Known For
- Acting
- Active Years
- 2012–2025 (14 Years)
- Total Credits
- 14 credits in database
Acting 14 credits
Biography
Tom O'Connell works in acting. Archytele tracks 14 screen credits across canonical film and television databases.
Advertisement
Advertisement
Ask the Vault
Ask anything about Tom O'Connell.
Frequent co-stars
Scout Taylor-Compton
1 shared title
Richard Dreyfuss
1 shared title
Stuart Townsend
1 shared title
Jon Seda
1 shared title
AnnaMaria Demara
1 shared title
Callum McGowan
1 shared title
Lorena Sarria
1 shared title
Ron Smoorenburg
1 shared title
Tofan Pirani
1 shared title
Quinn P Hensley
1 shared title
Career timeline
The PittInto the DeepDon't Let the Cat Out
Ahsoka
Obi-Wan KenobiObi-Wan Kenobi · Stunt Double
The Mandalorian · Stunt DoubleThe Mandalorian · StuntsL.A.'s Finest
Freshwater
The Equalizer · Stunt Double
Bullet to the Head · StuntsThe Baytown Outlaws
Full Filmography
14 titles- The Pitt (2025) as SWAT Dobrzycki
- Into the Deep (2025) as Chason
- Don't Let the Cat Out (2025) as Officer Rick
- Ahsoka (2023) as Darth Vader Performance Artist
- Obi-Wan Kenobi (2022) as Spice Den Guard #1
- Obi-Wan Kenobi (2022) Stunt Double
- The Mandalorian (2019) Stunt Double
- The Mandalorian (2019) Stunts
- L.A.'s Finest (2019) as Goon #2
- Freshwater (2017) as Agent Sam Colton
- The Equalizer (2014) Stunt Double
- Bullet to the Head (2012) Stunts
- The Baytown Outlaws (2012) as Denny / Cyborg in Movie
- Building Blocks as Security Guard
Frequently Asked Questions
What movies or TV shows is Tom O'Connell best known for?
Tom O'Connell is widely recognized for notable roles and projects including The Pitt (2025), Into the Deep (2025), Ahsoka (2023), Obi-Wan Kenobi (2022).
How many credits does Tom O'Connell have?
Tom O'Connell has accumulated over 14 film and television credits across a career spanning from 2012 to 2025.
Tom O'Connell by the numbers
14credits
7films
7TV series
2012–2025active years
What viewers say
No comments yet. Be the first to share your take on Tom O'Connell.