S1·E4 Lanakila (Victory)
Synopsis
A violent convict escapes from prison and kidnaps a young couple on vacation; McGarrett's estranged sister comes to town.
Episode recap
In the fourth episode of Hawaii Five-0, a violent convict escapes from prison and kidnaps a young couple on vacation. The governor's task force is tasked with tracking down the escaped convict and rescuing the hostages.
Meanwhile, McGarrett's estranged sister arrives in town. The episode focuses on the task force's efforts to apprehend the escaped convict and rescue the hostages, while also exploring the personal life of McGarrett.
The episode is part of the first season of the series, which premiered in 2010 and stars Alex O'Loughlin and Scott Caan. The series centers around a fictional special police major crimes task force operating at the behest of the governor of Hawaii.
The episode's plot is driven by the task force's investigation into the escaped convict's activities and their efforts to rescue the hostages. The episode also delves into the personal life of McGarrett, as his estranged sister's arrival in town sparks a range of emotions.
The episode is part of a larger narrative that explores the personal and professional lives of the characters, as well as the complexities of the task force's work. The series has received a range of reviews, with some critics praising its action-packed plot and others noting its more serious and dramatic tone.
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Frequently Asked Questions
When did Season 1 Episode 4 of Hawaii Five-0 air?
Season 1, Episode 4 ('Lanakila (Victory)') originally aired on October 11, 2010.
How long is Season 1 Episode 4 ('Lanakila (Victory)')?
The runtime for this episode is approximately 42 minutes.
What happens in Hawaii Five-0 Season 1 Episode 4?
A violent convict escapes from prison and kidnaps a young couple on vacation; McGarrett's estranged sister comes to town....